mohon bantuan. mtk ttg pytagoras. menentukan keliling segitiga, nomer 8

AD=8Cos60 =8.1/2=4
AC=AD/Cos30=4/(akar3 /2)=8/akar3
BC^2=AB^2 +AC^2-2AB.AC.Cos 90
=8^2 + (8/akar3)^2- 0
=64 + 64/3 = (192 + 64)/3 =156/3
BC =akar (156/3) = 16/akar3
keliling= AC+AB+BC
= (8/akar3) + 8 + (16/akar3)
= (24/akar3) + 8
= 8akar3 + 8.