Matematika

Pertanyaan

Diketahui f(x) = x²+4x-1 dan g(x) =6-2x tentukan (fog) (x) dan (gof) (x)

2 Jawaban

  • (fog)(x)=(6-2x)²+4(6-2x)-1=36-24x+4x²+24-8x-1=4x²-32x+59

    (gof)(x)=6-2(x²+4x-1)=6-2x²-8x+2=8-8x-2x²
  • f(x) = x²+4x-1
    g(x) = 6-2x
    (f o g)(x)
    = f(g(x))
    = f (6-2x)
    = (6-2x)² + 4(6-2x) -1
    = 6²- 24x+x² + 24-8x -1
    = 36 - 24x +x² + 24 - 8x - 1
    =x² - 32 + 59

    (g o f)(x)
    = g (f(x))
    = g (x²+4x-1)
    = 6 - 2(x²+4x-1)
    = 6 - 2x²-8x+2
    = -2x² - 8x + 8

    maaf kalo salah

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