tolong no. 6&7..makasih
Matematika
thegirlwithgod
Pertanyaan
tolong no. 6&7..makasih
2 Jawaban
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1. Jawaban SariZahiroh
6.
[tex]3 \frac{3}{4} - 1 \frac{1}{2} - 1 \frac{5}{6} = \frac{15}{4} - \frac{3}{2} - \frac{11}{6} = \frac{45 - 18 - 22}{12} = \\ \frac{5}{12} [/tex]
jadi luas sawah pak anshar pada petak ke tiga adalah
[tex] \frac{5}{12} [/tex]
7.
[tex]12.5 + 7 \frac{1}{2} - 30\% = \frac{125}{10} + \frac{15}{2} - \frac{30}{100} = \\ \frac{1250 + 750 - 30}{100} = \frac{1970}{100} = \frac{197}{10} = \\ 19 \frac{7}{10} [/tex]
jadi sisa buah ibu adalah
[tex]19 \frac{7}{10} [/tex] -
2. Jawaban Fazriah20
6.) 3 3/4 - 1 1/2 - 1 5/6
= 15/4 - 3/2 - 11/6
= 45/12 - 18/12 - 22/12
= 5/12
7.) 125/10 + 7 1/2 - 30/100
= 125/10 + 15/2 - 30/100
= 1250/100 + 750/100 - 30/100
= 1970/100 = 197/10
= 19 7/10