maaf mau tanya fisika caranya itu dua no aja

no 201
[tex]n = 2 \: (terang) \\ p = 3 \: mm = 3 \times {10}^{ - 3} \: m \\ d = 0.4 \: mm = 4 \times {10}^{ - 4} m \\ l = 1 \: m[/tex]
[tex]d. \frac{p}{l} = n.lamda \\ \frac{(4 \times {10}^{ - 4} ) \times (3 \times {10}^{ - 3} )}{1} = 2.lamda \\ \frac{4 \times 3 \times {10}^{ - 7} }{2} = lamda \\ 6 \times {10}^{ - 7} = lamda[/tex]
semoga membantu :)