Diketahui sudut ABC siku-siku di C dan cos A = 5/13. Nilai tan B adalah

Trigonometri


sisi istimewa
5, 12, 13

cos A = sin B = 5/13
cos B = sin A= 12/13

b^2 = c^2 - a^2
b^2 = 13^2 - 5^2
b^2 = 144
b = 12

tan B
= sin B / cos B
= 5/13/12/13
= 5/12

Sudut Istimewa ⬇️⬇️
5 x 13

Karena siku siku istimewa...
x² = 13² - 5²
x² = 169 - 25
x² = 144
x = 12

Bukti :
5² + 12² = 13²
25 + 144 = 169

Cos A = 5/13
Sin A = 12/13
Tan A = 12/5
Cos B = 12/13
Sin B = 5/13
Tan B = 5/12 ✔️

Semoga bermanfaat.....
-Prisco