[tex]3 \sqrt{15 \times 10 \div 3} [/tex] tolong bantu saya, sekalian caranya???

Kelas 9 Matematika
Bab 5 - Akar dan Pangkat

Penyelesaian:
[tex]3 \sqrt{15 \times 10 \div 3} \\ = 3 \sqrt{5 \times 10} \\ = 3 \sqrt{50} \\ = 3 \sqrt{25 } \times \sqrt{2} \\ = 3 \times 5 \sqrt{2} \\ = 15 \sqrt{2} [/tex]
Semoga Membantu^-^