sebanyak 250 ml larutan Na2Cro4 0,001M dicampurkan dalam gelas kimia dengan 250 ml larutan AgNO3 0,001 M (Ksp AgCrO4 = 1 X 10-12) tentukan apakah akan terjadi p

mol Na2CrO4 = 250mL x 0.001M = 0.25 mmol

Na2CrO4 => 2Na^+ + CrO4^2-
0.25mmol.....0.5mmol.....0.25mmol

mol AgNO3 = 250mL x 0.001M = 0.25 mmol

AgNO3 => Ag^+ + NO3^-
0.25........0.25..........0.25

volume total = (250+250)mL = 500 mL
[Ag^+] = 0.25mmol/500mL = 0.0005 M
[CrO4^2-] = 0.25mmol/500mL = 0.0005 M

Ag2CrO4 <=> 2Ag^+ + CrO4^2-

Qc = [Ag+]^2 [CrO4^2-]
Qc = [0.0005]^2 [0.0005]
Qc = 1.25 x 10^-10

Karena nilai Qc>Ksp, maka terbentuk endapan