persamaan garis singgung kurva y= x²+x-6 melalui titik (1,-4)?

f(x) = x^2 + x - 6
f'(x) = 2x + 1
f'(1) = 3
y - y0 = m(x - x0)
y + 4 = 3(x - 1)
y = 3x - 7