Tolong Di Bantu Dong No 2 Dan 3 Menggunakan Cara a Ya

Nomor 2

[tex] \sqrt{50} . 3 \sqrt{24} = 3 \sqrt{1200} =3 \sqrt{400.3} = 3.20 \sqrt{3} =60 \sqrt{3} [/tex]

Nomor 3

[tex] \frac{2}{3+ \sqrt{2} } . \frac{3- \sqrt{2} }{3- \sqrt{2} } = \frac{6-2 \sqrt{2} }{9-2} = \frac{6-2 \sqrt{2} }{7} [/tex]