Jika jumlah suku ke-n deret aritmatika dinyatakan dengan Sn=4n2+2n,maka U10=

Barder

Un = S(n) - S(n-1)
U10= S10- S9
U10
= 4(10)^2 + 2(10) - (4(9)^2 + 2(9)
= 400 + 20- 324 - 18
= 420- 342
= 78

U10 = S10 - S9
U10 = (4 (10²) + 2 (10)) - (4 (9²) + 2(9))
U10 = (400 + 20) - (324 + 18)
U10 = 420 - 342
U10 = 78 ✔️

Semoga bermanfaat.....
-Prisco