keliling bangun disamping adalah.....phi=22/7
Matematika
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Pertanyaan
keliling bangun disamping adalah.....phi=22/7
1 Jawaban
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1. Jawaban chenle
Panjang Busur Lingkaran
= [tex] \frac{1}{2} [/tex] × [tex] \frac{22}{7} [/tex] × 14
= 22 cm
↓
a = (26 - 14) ÷ 2
= 12 ÷ 2
= 6 cm
b = 15 - (14 ÷ 2)
= 15 - 7
= 8 cm
Panjang Sisi Miring Trapesium
c² = a² + b²
= 6² + 8²
= 36 + 64
= 100
c = √100 = 10 cm
↓
Keliling Bangun
= 26 + 10 + 10 + 22
= 68 cm.