bantuin lagi kak fisika
Fisika
dianendanglestar
Pertanyaan
bantuin lagi kak fisika
1 Jawaban
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1. Jawaban AnugerahRamot
FENOMENA KUANTUM
▶Frekuensi Cahaya
W₀ = 3,72 × 10⁻¹⁹ J
Ek = 2 × 10⁻¹⁹ J
Energi Foton :
E = W₀ + Ek
E = (3,72 + 2) × 10⁻¹⁹
E = 5,72 × 10⁻¹⁹ J
E = h f
5,72 × 10⁻¹⁹ = 6,63 × 10⁻³⁴ × f
f ≈ 8,63 × 10¹⁴ Hz ✔ [A]