bantu jawab yah besok dikumpulin
Matematika
Meryana20
Pertanyaan
bantu jawab yah besok dikumpulin
2 Jawaban
-
1. Jawaban nady4putri03
[tex]a. \: {2}^{ - 12} a^{8} \times {2}^{6} {a}^{7} \\ {2}^{ - 12 + 6} {a}^{8 + 7} \\ {2}^{6} {a}^{15} \\ \\ b. \: 3 \sqrt{2} + 6 \sqrt{3} - 5 \sqrt{2} - 2 \sqrt{4 \times 3} \\ 3 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{3} - 4 \sqrt{3} \\ - 2 \sqrt{2} - 10 \sqrt{3} [/tex] -
2. Jawaban PriscoMCM
A)...
[tex] = ( {2}^{3} {a}^{ - 2} ) {}^{ - 4} \times {2}^{6} {a}^{7} \\ = {2}^{ - 12} {a}^{8} \times {2}^{6} {a}^{7} \\ = {2}^{ - 12 + 6} {a}^{8 + 7} \\ = {2}^{ - 6} {a}^{15} \\ = \frac{1}{ {2}^{6} } {a}^{15} \\ = \frac{ {a}^{15} }{64}[/tex]
B)...
[tex]3 \sqrt{2} + 6 \sqrt{3} - 5 \sqrt{2} - 2 \sqrt{12} \\ = 3 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{3} -(2 \sqrt{4} \times \sqrt{3} ) \\ = 3 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{3} - 4 \sqrt{3} \\ = - 2 \sqrt{2} + 2 \sqrt{3} \\ = 2 \sqrt{3} - 2 \sqrt{2} [/tex]
Semoga bermanfaat.....
-Prisco