tolong dibantu yah. harus dikumpul besok

Mapel: Kimia
Kelas: X
Materi: Stoikiometri
Kata Kunci; Persamaan Gas Ideal

Jawab
Mr SO3 = 32+48 = 80g/mol

STP = 22,4
RTP = 24
Keadaan tertentu = V×P= R×T

n= gr/Mr
n= 0,8/80
n= 0.01mol

a) V= n×Vm
V= 0.01×24,4
V= 0.224L

b) V= n×R×T/P
V= 0,01×0.082×(273+27)/0,5
V= 0,492L

c)n1/V1 = n2/V2

0.01/V1 = 0,05/1

V1 ×0.05= 0.01×1
V1 = 0.01/0,05
V1= 0,2L

V1 = volume SO3
V2 = Volume CO2

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