soal matematika nomor 2 dan 3

Nomor 3
[tex]
\lim_{x \to 2} \frac {x^3-4x}{x-2}\\
=\lim_{x \to 2} \frac {x(x^2-4)}{x-2}\\
=\lim_{x \to 2} \frac {x(x+2)(x-2)}{x-2}\\
=\lim_{x \to 2} x(x+2)\\
=2(2+2)\\
=8


[/tex]